(4y^2-3y+3)-(5y^2-3y+4)=

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Solution for (4y^2-3y+3)-(5y^2-3y+4)= equation:


Simplifying
(4y2 + -3y + 3) + -1(5y2 + -3y + 4) = 0

Reorder the terms:
(3 + -3y + 4y2) + -1(5y2 + -3y + 4) = 0

Remove parenthesis around (3 + -3y + 4y2)
3 + -3y + 4y2 + -1(5y2 + -3y + 4) = 0

Reorder the terms:
3 + -3y + 4y2 + -1(4 + -3y + 5y2) = 0
3 + -3y + 4y2 + (4 * -1 + -3y * -1 + 5y2 * -1) = 0
3 + -3y + 4y2 + (-4 + 3y + -5y2) = 0

Reorder the terms:
3 + -4 + -3y + 3y + 4y2 + -5y2 = 0

Combine like terms: 3 + -4 = -1
-1 + -3y + 3y + 4y2 + -5y2 = 0

Combine like terms: -3y + 3y = 0
-1 + 0 + 4y2 + -5y2 = 0
-1 + 4y2 + -5y2 = 0

Combine like terms: 4y2 + -5y2 = -1y2
-1 + -1y2 = 0

Solving
-1 + -1y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -1y2 = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -1y2 = 0 + 1
-1y2 = 0 + 1

Combine like terms: 0 + 1 = 1
-1y2 = 1

Divide each side by '-1'.
y2 = -1

Simplifying
y2 = -1

Reorder the terms:
1 + y2 = -1 + 1

Combine like terms: -1 + 1 = 0
1 + y2 = 0

The solution to this equation could not be determined.

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